1sin10°-√3cos10°=
1
0
2
4
Explanation for the correct option:
Simplify using standard trigonometric identities
Let S=1sin10o−3cos10o
Multiply and divide by 2:
⇒S=212sin10o−32cos10o
⇒S=2sin30osin10o−cos30ocos10o ∵sin30°=12,cos30°=32
⇒S=2sin30ocos10o−cos30osin10osin10ocos10o
⇒S=2sin20osin10ocos10o ∵sinAcosB-cosAsinB=sin(A-B)
⇒S=2×2sin10ocos10osin10ocos10o ∵sin2θ=2sinθcosθ
⇒S=4
Hence, Option ‘D’ is Correct.
Evaluate : (i) (47)3 (ii) (1011)3 (iii) (115)3 (iv) (1310)3