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Question

1+sin2x/1-sin2x=tan​​​​2(45°+x)

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Solution

Given that

(1-sin2x)/(1+sin2x)

=(sin90-sin2x)/(sin90+sin2x)

={2cos(90+2x)/2.sin(90-2x)/2}/2sin(90+2x)/2.cos(90-2x)/2

=cot(45+x).tan(45-x)

=cot{90-(45-x)}.tan(45-x)

=tan^2(45-x) =RHS

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