1g mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy (γ=1.4).
A
1169.5J
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B
769.5J
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C
−1369.5J
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D
−969.5J
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Solution
The correct option is C−1369.5J Use T1Vγ−11=T2Vγ−12 Given:V2=2V1 or T2=T1Vγ−11Vγ−12=273(2)0.4=207K Change in internal energy ΔU=CvΔT=R(γ−1)(T2−T1) =−8.31(273−207)1.4−1=−1369.5J