1. The accuracy in the measurement of the diameter of hydrogen atom as $1.06 \times 10^{- 10} m$ is

0.11

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106 \times 10^{10}

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\frac{1}{106}

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0.01 \times 10

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Solution

The correct option is A $0.11$
Actual diameter of hydrogen atom is $D = 120 p m = 120 \times 10^{- 12} m$

Given diameter is $D^{'} = 1.06 \times 10^{- 10} m = 106 \times 10^{- 12} m$

$a c c u r a c y = ∣ ∣ ∣ \frac{exp e r i m e n t a l - t r u e}{t r u e} ∣ ∣ ∣$

$= ∣ ∣ ∣ \frac{106 - 120}{120} ∣ ∣ ∣$

$= \frac{14}{120}$

$= 0.11$

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