1.The partial change(s) developed on the ends of dipoles is. a)>1.6×10^-19 C. b)<1.6×10^-19 C. c)equal to 1.6×10^-19 CC. d)None of the above

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Solution

The ends of the dipole are q+ and q-. Positive end and negative end.
positive end with q+ charge , the charge is +1.6 x 10^-19 C
negative end with q- charge, the chrage is -1.6 x 10^-19 C.
The magnitude of the charge develeoped at the ends of dipole will be without sign, that is 1.6 x 10^-19 C.

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1.The partial change(s) developed on the ends of dipoles is. a)>1.6×10^-19 C. b)<1.6×10^-19 C. c)equal to 1.6×10^-19 CC. d)None of the above

The ends of the dipole are q+ and q-. Positive end and negative end. positive end with q+ charge , the charge is +1.6 x 10^-19 C negative end with q- charge, the chrage is -1.6 x 10^-19 C. The magnitude of the charge develeoped at the ends of dipole will be without sign, that is 1.6 x 10^-19 C.

The ends of the dipole are q+ and q-. Positive end and negative end.
positive end with q+ charge , the charge is +1.6 x 10^-19 C
negative end with q- charge, the chrage is -1.6 x 10^-19 C.
The magnitude of the charge develeoped at the ends of dipole will be without sign, that is 1.6 x 10^-19 C.