1. The pressure of value water at the ground levels is $196000 N m^{-} 2$ and at the third floor is $98000 N m^{-} 2$
What is the height of third floor?
2. Define specific gravity.

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Solution

Given,

Pressure difference, $Δ P = 196000 - 98000 = 98000 N m^{- 2}$

Pressure difference, $Δ P = ρ g Δ h$

Where, $ρ =$ density of liquid

$Δ h$ = height difference

$Δ P = ρ g Δ h$

$98000 = 1000 \times 9.8 \times Δ h$

$Δ h = 10 m$
Hence, third floor is at $10 m$ from ground. Specific gravity: The ratio of the density of a substance to the density of some substance (such as pure water) taken as a standard when both densities are obtained by weighing in air

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1. The pressure of value water at the ground levels is 196000Nm−2 and at the third floor is 98000Nm−2 What is the height of third floor?2. Define specific gravity.

1. The pressure of value water at the ground levels is $196000 N m^{-} 2$ and at the third floor is $98000 N m^{-} 2$
What is the height of third floor?
2. Define specific gravity.