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Ohm's Law

1 Vm -1 equal

Question

1 Vm^-1equal

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Solution

An alternative unit for electric field intensity may be derived as follows.

Since Joules = Volts x coulombs = Newtons x metres (J = VC = Nm) we can write NC^-1 as [VC/m]C^-1 = Vm^-1. The electric field intensity may also be expressed in volts per metre (Vm^-1).

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Similar questions

1 V m^{- 1}

Q. In a plane electromagnetic wave, the electric field of amplitude

1 V m^{- 1}

varies with time in free space. The average energy density of magnetic field is (in

J m^{- 2}

Q. A dipole of dipole moment 'p' is placed in non-uniform electric field along x-axis. Electric field is increasing at the rate of

1 V m^{- 1}

. The force on dipole is:

t \in R

[t]

be the greatest integer less than or equal to

t

lim x \to 1^{+} \frac{(1 - | x | + sin | 1 - x |) sin (\frac{π}{2} [1 - x])}{| 1 - x | [1 - x]}

	Column - I		Column - II
(A)	$\sum_{r = 1}^{n} r .^{n} C_{r}$ is equal to	(P)	$(n + 2) {.2}^{n - 1}$
(B)	$\sum_{r = 1}^{n + 1} r .^{n} C_{r - 1}$ is equal to	(Q)	$(n + 1) .^{2 n} C_{n}$
(C)	$\sum_{r = 0}^{n} (2 r + 1) .^{n} C_{r}$ is equal to	(R)	$(n + 1) {.2}^{n}$
(D)	$\sum_{r = 0}^{n} (2 r + 1) . (^{n} C_{r})^{2}$ is equal to	(S)	$n {.2}^{n - 1}$

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