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Question

(1+x2)dydx+2xy=cosx

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Solution

(1+x2)dydx+2xy=cosx

dydx+2xy1+x2=cosx1+x2

dydx+Py=Q

P=2x1+x2,Q=cosx1+x2

IF=ePdx

=e2x1+x2dx

IF=1+x2

y×IF=Q×IFdx+c

y×(1+x2)=cosx1+x2×(1+x2)dx+c

y×(1+x2)=cosxdx+c

y(1+x2)=sinx+c

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