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Density

10.0 cm from ...

Question

$10.0$ cm from the centre of the pipe (half way between the centre and the walls)

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Solution

$v = \frac{P_{1} - P_{2}}{4 η L} (R^{2} - r^{2})$
or $v \propto R^{2} - r^{2}$
$\frac{v_{1}}{v_{2}} = \frac{R^{2} - r_{2}^{2}}{R^{2} - r_{2}^{2}}$
or $\frac{3}{v_{2}} = \frac{400 - 0}{400 - 100}$
$∴$ $v_{1} = 2.25$ m/s

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