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Question

1010log10csc(10x) differentiate w.r.t. x

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Solution

Solution:-
1010log10csc10x
Differentiating w.r.t. x, we have
dydx(1010log10csc10x)
Differentiating according to chain rule, we have
=(1010log10csc10xlog10)×(10log10csc10xlog10)×(1csc10x×(csc10xcot10x.)×10)
dydx(1010log10csc10x)=(1010log10csc10x)×(10log10csc10x)×(cot10x×10)
Hence dydx=10cot(10x)(1010log10csc10x)×(10log10csc10x)

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