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Arrhenius Acid

10.30 mg of O...

Question

10.30 mg of $O_{2}$ dissolved into a litre of sea water of density 1.03g/mL. The concentration of $O_{2}$ in ppm is

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Solution

$ppm = \frac{W_{Solute}}{W_{Solution}} \times 100$
Using the density of the solution and its volume $(1 L = 1000 mL = 1000 {cm}^{3})$ , the weight of the solution can be calculated.
$W_{solution} = 1.03 \times 1000 = 1030 g$
Thus, ppm $\frac{10.3 \times 10^{- 3} g}{1030 g} \times 10^{6} = 10 p p m$

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