10, 5, 13, 10, 16, 20, 19, (....)

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Solution

The correct option is B 40
There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.

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$\frac{1}{1 \times 4} + \frac{1}{4 \times 7} + \frac{1}{7 \times 10} + \frac{1}{10 \times 13} + \frac{1}{13 \times 16} + \frac{1}{16 \times 19}$ =

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