Question

10 A current deposits 10.8 gm silver in 900s. The mass of copper deposited by 9A current in 1200s will be

• A. 12.7 gm
• B. 10.8 gm
• C. 6.35 gm
• D. 3.8 gm

Answer 1

The correct option is D 3.8 gm

Given : $I_{Ag}=10$ A $W_{Ag}=10.8$ gm $t_{Ag}=900$ s $I_{Cu}=9$ A $t_{Cu}=1200$ s

Equivalent weight of copper $E_{Cu}=\frac{63.5}{2}=31.75$ gm/mol

Equivalent weight of silver $E_{Ag}=108$ gm/mol

$\therefore$ $\frac{W_{Cu}}{W_{Ag}}=\frac{E_{Cu}{I}_{Cu}{t}_{Cu}}{E_{Ag}{I}_{Ag}{t}_{Ag}}$

$\therefore$ $\frac{W_{Cu}}{10.8}=\frac{\left(31.75\right)\left(9\right)\left(1200\right)}{\left(108\right)\left(10\right)\left(900\right)}$ $⟹W_{Cu}=3.8$ gm