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Question

10C1 + 10C3 + 10C5 + 10C7 + 10C9 =


A

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B

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C

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D

None of these

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Solution

The correct option is A


We know that

2n−1 = nC0 + nC2 +nC4 + ..........= nC1 + nC3 + nC5 +........

So, 10C1 + 10C3 + 10C5 + .........+ 10C9 = 210−1 = 29


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