Question

10 chocolates are distributed in the ratio 2 : 3 between A and B respectively. B further divided the chocolates with him between C and D equally. If D gives back all the chocolates with him to A, what is the final number of chocolates with A ?

• A. 5
• B. 6
• C. 7
• D. 8

Answer 1

The correct option is C 7

Sum of the terms of the ratio = 2 + 3 = 5
$\Rightarrow$ Value of 5 parts = 10 chocolates
$\Rightarrow$ Value of 1 part = $\frac{10}{5}=2$ chocolates

$\therefore$ A gets 2 parts = $2\times 2=4$ chocolates
B gets 3 parts = $3\times 2=6$ chocolates

Further, B divides the chocolates with him equally between C and D
$\Rightarrow$ C and D get 3 chocolates respectively.

$\because$ D gives all his chocolates to A

The final number of chocolates with A = 4 + 3 = 7.