Question

10 g ice at 0°C is mixed with 20 g of water at 20°C. What is the temperature of mixture?

Answer 1

The final temperature of the mixture:

$$\begin{gathered} T=\frac{m_{1}c{t}_1+m_{2}c{t}_2}{m_{1}c+m_{2}c} \\ =\frac{m_1{t}_1+m_2{t}_2}{m_1+m_2} \\ =\frac{(10\times 273)+(20\times 293)}{10+20} \\ =\frac{2730+5860}{30} \\ =286.3K=13.3{}^{0}C. \end{gathered}$$