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Mole Concept

10 g mixture ...

Question

$10$ g mixture of $N a H C O_{3}$ and $N a_{2} C O_{3}$ has $1.68$ g $N a H C O_{3}$ . It is heated at $400$ K. Weight of the residue will be :

A

9.38

g

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B

8.32

g

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C

10.0

g

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D

1.68

g

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Solution

The correct option is A $9.38$ g
$2 N a H C O_{3} H e a t - -- \to N a_{2} C O_{3} + H_{2} O + C O_{2} ↑$
The molar mass of $N a H C O_{3}$ is 84 g/mol.
The molar masses of $C O_{2}$ and water are 44 g/mol and 18 g/mol respectively.
Thus, $2 \times 84 = 168$ g of $N a H C O_{3}$ on decomposition will loose $44 + 18 = 62$ g.
Hence, 1.68 g of $N a H C O_{3}$ on decomposition will lose 0.62 g.
Hence, the weight of the residue will be $10 - 0.62 = 9.38$ g.

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