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Question

10 g of a certain non-volatile solute was dissolved in 100 g of water at 20oC. The vapour pressure was lowered from 17.3555 to 17.235 mm. Calculate the molecular mass of the solute.

A
257.45
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B
27.45
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C
157.45
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D
200.45
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Solution

The correct option is A 257.45
We have lowering of vapour pressure
P0BPtP0B=xA
moles of water = 5.55moles
moles of non-volatile solute = x
so we have

17.355517.23517.3555=xx+5.55

x = 0.039
molecular weight of solute = 100.039 = 257.45



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