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Mixture

10 g of bleac...

Question

10 g of bleaching powder is dissolved in water containing some ${C H}_{3} C O O H$ and diluted to 1 L. 20 ml of this solution on reaction with $K I$ required 20 ml of 0.1 $N {N a}_{2} S_{2} O_{3}$ solution. Calculate percentage of available chlorine in it.

35.5%

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71%

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17.75%

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142%

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None of the above

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Solution

The correct option is A 35.5%
$C a O C l_{2} + 2 C H_{3} C O O H \to C l_{2} + H_{2} O + C a (C H_{3} C O O)_{2}$

$C l_{2} + 2 K I \to 2 K C l + I_{2}$
n-factor for $C l_{2}$ = 2

$2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}$
$N_{1} V_{1} = N_{2} V_{2}$
$N_{1} \times 20 = 0.1 \times 20$
$N_{1} = 0.1 N$

20 mL 0.1 N $N a_{2} S_{2} O_{3}$ = 2 x 20 mL 0.1 N $I_{2}$ ≡ 2x 20 mL 0.1 N $C l_{2}$

Amount of chlorine in 0.1 N and 20 ml solution

Formula used $N o r m a l i t y = M o l a r i t y \times n - f a c t o r$

Amount of chlorine = $\frac{35.5 \times 0.1}{1000 \times 2} \times 20 = 0.035 g$

% of available chlorine = $\frac{0.035}{10} \times 100 = 0.35$

35 % is available chlorine.

A is the correct answer

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10 g of bleaching powder is dissolved in water containing some CH3COOH and diluted to 1 L. 20 ml of this solution on reaction with KI required 20 ml of 0.1 N Na2S2O3 solution. Calculate percentage of available chlorine in it.

10 g of bleaching powder is dissolved in water containing some ${C H}_{3} C O O H$ and diluted to 1 L. 20 ml of this solution on reaction with $K I$ required 20 ml of 0.1 $N {N a}_{2} S_{2} O_{3}$ solution. Calculate percentage of available chlorine in it.