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Byju's Answer

Standard X

Chemistry

Mole Concept

10 g of CaC...

Question

$10$ g of $C a C O_{3}$ contains:

10

moles of

C a C O_{3}

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0.1

g atom of

C

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6 \times 10^{23}

atoms of

C a

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0.1

of equivalent of

C a

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Solution

The correct option is D $0.1$ g atom of $C$
Molecular weight of $C a C O_{3} = 40 + 12 + 48 = 100$
Moles of $C a C O_{3}$ in $10 g = \frac{10}{100}$ $= 0.1 m o l = 0.1 g a t o m$

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10 g of CaCO3 contains:

The correct option is D 0.1 g atom of CMolecular weight of CaCO3=40+12+48=100Moles of CaCO3 in 10g=10100 =0.1mol=0.1gatom

$10$ g of $C a C O_{3}$ contains:

The correct option is D $0.1$ g atom of $C$
Molecular weight of $C a C O_{3} = 40 + 12 + 48 = 100$
Moles of $C a C O_{3}$ in $10 g = \frac{10}{100}$ $= 0.1 m o l = 0.1 g a t o m$