Question

$10$ g of $CaC{O}_3$ was dissolved in $250$ mL of $1MHCl$ and the solution was boiled. What volume of $2M$ $KOH$ would be required to obtain the equivalence point after boiling? Assume no change in volume during boiling.

• A. $V=100$ mL
• B. $V=50$ mL
• C. $V=12.5$ mL
• D. $V=25$ mL

Answer 1

The correct option is D $V=25$ mL

As given,

$\underset{0.1mole}{CaC{O}_3}+\underset{0.25mol}{2HCl}\to CaC{l}_2+C{O}_2+H_{2}O$
0 mol 0.05 mol

$\underset{0.05}{HCl}+\underset{2\times V}{KOH}\to KCl+H_{2}O$

$V=\frac{0.05}{2}lit$

$V=25$ mL

Hence, volume required is $25$ mL.