Question

10 g of ice at 0°c is added to 10 g of water at 80°c such that the final temp. of the mixture is 0°c.Calculate the sp.latent heat of ice? ( S.H.C. of water = 4.2 J/g/°c)

Answer 1

Dear Student
$$\begin{gathered} Q_{gainedbyice}=Q_{lostbywater} \\ mL=m_{water}{c}_{water}∆T \\ 10L=\left(10\right)(4.2)(80-0) \\ 10L=3360 \\ L=336J/g^{o}C \end{gathered}$$

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