Question

10 g of ice at 0${}^{\circ }C$ absorbs 5460 J of heat energy to melt and change t water at 50${}^{\circ }C$. Calculate the specific latent heat of fusion of ice. (Specific heat capacity of water is 4200 J $K{g}^{-1}{K}^{-1}$.

• A. 330 Jg^-1
• B. 336 Jg^-1
• C. 392 Jg^-1
• D. 350 Jg^-1

Answer 1

The correct option is B

336 Jg^-1

Let specific latent heat of fusion of ice = L

Heat required changing ice at 0${}^{\circ }C$ to water 0${}^{\circ }C$ + 50${}^{\circ }C$

Heat required = 10 L + $\frac{10\times 4200}{1000\times (50–0)}$ = 5460

$Q=10L+2100$

$10L=3360$

L = $\frac{3360}{10}$= 336 $J{g}^{-1}$