Question

$$10$$ g of ice at $$0^{\circ}C$$ absorbs $$5460$$ J of heat energy to melt and change to water at $$50^{\circ}C$$. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is $$4200 J kg^{-1} K^{-1}$$.

A
2168Jg1
B
336Jg1
C
43.36Jg1
D
21.68Jg1

Solution

The correct option is B $$336 Jg^{-1}$$Heat absorb =$$mL+mc\times (T-0)$$$$5460=10\times L+10\times 4.2\times 50$$$$L=336Jg^{-1}$$Chemistry

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