10 g of ice at 0 ice at 00 C is mixed with m mass of water at 500 C- What is minimum value of m so that ice melts completely- L -80 cal - g and s -1 cal - -g -0 C A- 16 gB- 32 gC- 20 gD- 40 g

The correct option is A 16 g ...

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Standard XII

Chemistry

Depression in Freezing Point

10 g of ice a...

Question

10 g of ice at 0 ice at 0⁰C is mixed with m mass of water at 50⁰ C. What is minimum value of m so that ice melts completely?( L = 80 cal/g and s = 1 cal/ g-⁰C)

32 g

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20 g

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40 g

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16 g

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Solution

The correct option is D
16 g

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Similar questions

10 g of ice at 0 ice at 0⁰C is mixed with m mass of water at 50⁰ C. What is minimum value of m so that ice melts completely?( L = 80 cal/g and s = 1 cal/ g-⁰C)

Q. What will be the final temperature when

150 g

of ice at

0^{\circ} C

is mixed with

300 g

of water at

50^{\circ} C

? Specific heat of water

= 1 c a l / g^{\circ} C

. Latent heat of fusion of ice

= 80 c a l / g

150 g

of ice is mixed with

100 g

of water at temperature

80^{o} C

. The latent heal of ice is

80 c a l / g

and the specific heat of water is

1 c a l / g^{o} C

. Assuming no heat loss to the environment, the amount of ice which does not melt is :

Q. One gram of steam at

100^{0} C

is added to m gram of ice at

0^{0} C

.What is the mass of ice that will melt and reach the temperature of steam water at

100^{0} C

[L_{i c e} = 80 c a l / g r a m a n d L_{s t e a m} = 540 c a l / g r a m]

Find the amount of heat in calories required to convert 10g of ice at –10°C to water at 10°C

[C of ice = 0.5 cal/g°C, C of water = 4.2J/g°C = 1 cal/g°C, L of ice = 80cal/g]

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10 g of ice at 0 ice at 00C is mixed with m mass of water at 500 C. What is minimum value of m so that ice melts completely?( L = 80 cal/g and s = 1 cal/ g-0C)

The correct option is D 16 g

10 g of ice at 0 ice at 0⁰C is mixed with m mass of water at 50⁰ C. What is minimum value of m so that ice melts completely?( L = 80 cal/g and s = 1 cal/ g-⁰C)

The correct option is D
16 g