Question

$10$ g of ice at 0${}^o$C absorbs $5460$ J of heat energy to melt and change to water at $50$${}^o$C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is $4200$ J kg${}^{-1}$ K${}^{-1}$

• A. 136 J g${}^{-1}$
• B. 236 J g${}^{-1}$
• C. 336 J g${}^{-1}$
• D. 436 J g${}^{-1}$

Answer 1

Answer: (C)

336 J g${}^{-1}$

$Q=5460=10\times L+10\times 4.2\times 50$

$L=336J{g}^{-1}$