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Question

10 g of ice at 20oC is dropped into a calorimeter containing 10 g of water at 10oC ; the specific heat of water is twice that of ice. When equilibrium is reached, the calorimeter will contain:

A
20 g of water
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B
20 g of ice
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C
10 g ice and 10 g water
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D
5 g ice and 15 g water
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Solution

The correct option is C 10 g ice and 10 g water
According to principle of calorimetry,
Heatgainedbyice=(10×80)+10×0.5(0(20))
800+100=900cal
Heatlostbywater=10×1×(100)+80×10
=900cal
Heatlost=Heatgained
At equilibrium, the calorimeter will contain 10 g of ice and 10 g of water.

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