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Question

10 g of liquid at 300 K are heated to 350 K. The liquid absorbs 6 kcal. What is the specific heat of the liquid (in cal/gC)?

A
6
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B
12
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C
60
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D
120
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E
600
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Solution

The correct option is E 12

Answer(B)
liquid is heated from 300k to 350k so temperature difference =50K
so C=Q/(mT)=6000/(1050)=12cal/gC

546765_496932_ans.JPG

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