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Byju's Answer
Standard XII
Chemistry
Nucleophilic Addition at the Carbonyl
10 g of Mno2 ...
Question
10 g of Mno2 on reaction with HCI forms 2.24 L of Cl2(g) at NTP, the percentage impurity of MnO2 is (1) (3) 87% (2) 25% (4) 13% 33.3%
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Q.
10
g
of
M
n
O
2
on reaction with HCI forms
2.24
L
of
C
I
2
(
g
)
at NTP, the percentage impurity of
M
n
O
2
is:
M
n
O
2
+
4
H
C
I
→
M
n
C
I
2
+
C
I
2
+
2
H
2
O
Q.
10
g of
M
n
O
2
on reaction with conc.
H
C
l
liberated
0.1
equivalent of
C
l
2
(molecular weight of
M
n
=
55
g/mol). Hence, percentage purity of
M
n
O
2
is
:
Q.
The percentage of
M
n
O
2
in a mineral specimen is
y
×
10
−
1
. If the iodine liberated by a
0.1344
g sample in the net reaction,
M
n
O
2
(
s
)
+
4
H
+
+
2
I
−
→
M
n
2
+
+
I
2
+
2
H
2
O
, require
32.30
mL of
0.07220
M
N
a
2
S
2
O
3
. Then,
y
is
(
M
n
O
2
=
87
g
m
o
l
−
1
)
:
Q.
Chlorine can be prepared by reacting MCI with
M
n
O
2
. The reaction is represented by the equation,
M
n
O
2
(
s
)
+
4
H
C
I
(
a
q
.
)
→
C
l
2
(
g
)
+
M
n
C
l
2
(
a
q
.
)
+
2
H
2
O
(
l
)
Assuming that the reaction goes to completion, what mass of cone. HCI solution (36% HCI by mass) is needed to produce 2.5 g
C
l
2
?
Q.
M
n
O
2
(
s
)
+
4
H
C
l
(
a
q
)
H
e
a
t
−
−−
→
M
n
C
l
2
(
a
q
.
)
+
2
H
2
O
+
C
l
2
(
g
)
The equivalent weight of
M
n
O
2
in the above reaction is:
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