Question

10 g of $NaOH$ required a certain amount of $H_{2}S{O}_4$ or complete neutralization. Calculate the number of moles of $H_{2}S{O}_4$ required.

• A. 1 mole
• B. 0.1 mole
• C. 0.5 mole
• D. 0.125 mole

Answer 1

The correct option is D 0.125 mole

10 g of $NaOH$ (molar mass 40 g/mol) $=\frac{10g}{40g/mol}=0.25mole$

$2NaOH+H_{2}S{O}_4\to N{a}_{2}S{O}_4+2H_{2}O$

0.25 mole of $NaOH$ will react with $\frac{0.25}{2}=0.125$ mole of $H_{2}S{O}_4$.

So, the no. of moles of $H_{2}S{O}_4$ require to neutralize 10 g of $NaOH$ is 0.125 mole.

Hence, the correct option is D.