Question

10 gm of a gas at 1 atm and 273 K occupies 5 litres. The temperature at which the volume becomes double for the the mass of gas at the same pressure is :

• A. $273K$
• B. $-{273}^{\circ }C$
• C. ${250}^{\circ }C$
• D. ${546}^{\circ }K$

Answer 1

The correct option is D ${546}^{\circ }K$

$\begin{array}{cc}\text{Given}& \Rightarrow P=1\text{atm}\\ T_1& =273K{T}_2=?\\ V_1& =5L{V}_2=2V_1=2\times 5=10L\end{array}$

Using charle's fow : $\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{\text{We get:}}{\text{T.}}\frac{5}{273}=\frac{10}{T_1}$

$T_1=\frac{273\times 10}{5}=273\times 2=546k$

Thus, at $546K$, the volume beccomes double for the mass of gas at same pressure