Question

$10$gm of ice at $-{20}^o$C is added to $10$gm of water at ${10}^o$C. Then find the final temperature of the mixture.

Answer 1

Heat required to melt ice at $-{20}^{o}C$ into water at $0^{o}C$ is

$10\times 0.5\times [0-(-20\left)\right]+10\times 80=100+800=900cal$

Heat released by water at ${10}^{o}C$ $=10\times 1(10-0)=100cal$

Because required heat is much more than that of released heat. So, final temperature of the mixture is 0%