Question

10 grams of hydrogen and 142 grams of chlorine are made to react with each other. The remaining amount of reactant gas is made to react with excess oxygen. The same amount of the above reactant gas is made to react with nitrogen. Calculate the amounts of the products formed in both reactions.

• A. 3 moles of $H_{2}O$ and 2 moles of $N{H}_3$
• B. 2 moles of $H_{2}O$ and 3 moles of $N{H}_3$
• C. 3 moles of $H_{2}O$ and 3 moles of $N{H}_3$
• D. 2 moles of $H_{2}O$ and 2 moles of $N{H}_3$

Answer 1

Answer: (A)

3 moles of $H_{2}O$ and 2 moles of $N{H}_3$

reaction 1

$H_2+C{l}_2\to 2HCl$

hydrogen is 10 gram = 5 mol and cloride is 14 gram = 2 mole

we get 4 mol of HCl

when 4 mol of HCl formed 3 mol of h2 is reaming

reaming gas react with oxygen and nitrogen

$2H_2+O_2\to 2H_{2}O$

react 3 mol of hydrogen and 1.5 ml of oxygen formed 3 mol of water

3 mol of hydrogen react with nitrogen formed 2 mol of $N_3$

ans is A