Question

10 J of work is done in moving $12.5\times {10}^{18}$ electrons from one end to the other end of a conductor. What is the potential difference between the two ends of conductor?

• A. 2.5 volt
• B. 5 volt
• C. 10 volt
• D. 0 (zero) volt

Answer 1

The correct option is B 5 volt

Given:

Total charge passing $Q=1.25\times {10}^{18}\times 1\text{electronic charge}=1.25\times {10}^{18}\times 1.6\times {10}^{-19}C=2C$

Work done $W=10J$

Potential difference $\Delta V=?$

Formula: $\text{Work done}\left(W\right)=Q\Delta V$

$\therefore \Delta V=\frac{W}{Q}=\frac{10}{2}=5V$