10 kg ball is dropped from a height of 10 m. What is the speed of the ball just before it reaches the ground?
14 m/s
At the height of 10 m, the potential energy = mgh
10 kg x 9.8 m/s2 x 10 m = 980 J
Now, let the speed of the ball just before it reaches the ground be v
Then, kinetic energy = 1/2 x mv2
980 = 1/2 x 10 x v2
v = 14 m/s