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Question

10 L of a monoatomic ideal gas at 0oC and 5 atm is suddenly released to 1 atm pressure and the gas is expanded adiabatically against the constant pressure. Find the final volume (in L) of the gas.

A
54 L
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B
10 L
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C
34 L
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D
74 L
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Solution

The correct option is C 34 L
For an adiabatic process q=0,
From the First law, ΔU=q+w
For an adiabatic irreversible process, w=Pext(V2V1)
w=U=P2V2P1V1γ1
Pext(V2V1) = P2V2P1V1γ1

For a monoatomic gas, γ = 1.67
putting all the values,
1(V210) = 1×V25×10γ1
10V2 = V2500.67
(10V2)×0.67=(V250)
V2= 34 L

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