10 3x- 4 x 2 -3 3x- 4 x -7 is equal to

The correct option is C ( 3x 4 x 1 ) ( 30x 40 x +7 ) [ 10( 3x 4 x #160;) #160;+7 ] [ ( 3x 4 x #160;) 1 ] Let 3x 4x=a . Then ...

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Byju's Answer

Standard XII

Mathematics

Sum of Coefficients of All Terms

10 3x- 4 x 2...

Question

$10 {(3 x - \frac{4}{x})}^{2} - 3 (3 x - \frac{4}{x}) - 7$ is equal to

(3 x - \frac{4}{x} + 7) (3 x - \frac{4}{x} - 10)

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(3 x - \frac{4}{x} - 14) (3 x - \frac{4}{x} + 5)

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(3 x - \frac{4}{x} - 1) (30 x - \frac{40}{x} + 7)

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(3 x - \frac{4}{x} - 1) (3 x - \frac{4}{x} - + 7)

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Solution

The correct option is C $(3 x - \frac{4}{x} - 1) (30 x - \frac{40}{x} + 7)$
$[10 (3 x - \frac{4}{x}) + 7] [(3 x - \frac{4}{x}) - 1]$
Let $3 x - \frac{4}{x} = a$ . Then the expression becomes
$10 a^{2} - 3 a - 7$
$= 10 a^{2} - 10 a + 7 a - 7$
$= 10 a (a - 1) + 7 (a - 1)$
$= (10 a + 7) (a - 1)$
$[10 (3 x - \frac{4}{x}) + 7] [(3 x - \frac{4}{x}) - 1]$
$= [(30 x - \frac{40}{x}) + 7] [(3 x - \frac{4}{x}) - 1]$

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Similar questions

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

\int \frac{1}{[(x - 1)^{3} (x + 2)^{5}]^{1 / 4}} d x

is equal to

Q. Show that

\frac{1}{7} \leq \frac{x^{2} - 3 x + 4}{x^{2} + 3 x + 4} \leq 7

Solve :

$\frac{9 x - 7}{3 x + 5} = \frac{3 x - 4}{x + 6}$

Q. Factorize:

(i)

x^{3} + 3 x^{2} + 3 x - 7

(ii)

x^{3} - 3 x^{2} + 3 x + 7

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10(3x−4x)2−3(3x−4x)−7 is equal to

The correct option is C (3x−4x−1)(30x−40x+7)[10(3x−4x)+7][(3x−4x)−1]Let 3x−4x=a. Then the expression becomes10a2−3a−7=10a2−10a+7a−7=10a(a−1)+7(a−1)=(10a+7)(a−1)[10(3x−4x)+7][(3x−4x)−1]=[(30x−40x)+7][(3x−4x)−1]

$10 {(3 x - \frac{4}{x})}^{2} - 3 (3 x - \frac{4}{x}) - 7$ is equal to