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Standard XII

Chemistry

Introduction

10 lt box c...

Question

10 $l t$ box contain $O_{3}$ and $O_{2}$ at equilibrium at 2000 K. The $Δ G^{o} = - 534.52 k J$ at 8 atm equilibrium pressure. The following equilibrium is present in the container,
$2 O_{3} (g) ⇌ 3 O_{2} (g)$ . The partial pressure of O $_{3}$ will be___________. $(l n 10 = 2.3, R = 8.3 J m o l e^{- 1} K^{- 1}$ )

8 \times 10^{- 6}

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22.62 \times 10^{- 7}

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9.71 \times 10^{- 6}

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9.7 \times 10^{- 2}

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Solution

The correct option is B $22.62 \times 10^{- 7}$
$Δ G^{o} = - R T l n K = - 2.3 \times 2000 \times 8.3 l o g K$
$\frac{534. 52 \times 10^{3}}{2.3 \times 8.3 \times 2000} = l o g K$
$K = 10^{14}$
$2 O_{3} (g) ⇌ 3 O_{2} (g)$ $K = 10^{14}$
So, $P_{o_{3}} <<< P_{o_{2}}$
So, $P_{o_{2}} + P_{o_{3}} = 8$
$P_{o_{2}} = 8 a t m$
$K = 10^{14} = \frac{(P_{o_{2}})^{3}}{(P_{o_{3}})^{2}} = \frac{(8)^{3}}{P_{o_{3}}}$
$P_{o_{3}} = 22. 62 \times 10^{- 7} a t m$

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