Question

10 men and 15 women together can complete a work in 6 days. It takes 100 days for 1 man alone to complete the same work. How many days will be required for one woman alone to complete the same work?

• A. 90
• B. 125
• C. 145
• D. 150
• E. None of these

Answer 1

The correct option is E

None of these

1 man's 1 day's work $=\frac{1}{100}$ (10 men + 15 women)'s 1 day's work $=\frac{1}{6}$
15 women's 1 day's work $=(\frac{1}{6}-\frac{10}{100})=(\frac{1}{6}-\frac{1}{10})=\frac{1}{15}$
1 woman's 1 day's work $=\frac{1}{225}$
$\therefore$ 1 woman alone can complete the work in 225 days.