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Question

10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work ?

A
90
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B
225
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C
145
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D
150
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E
None of these
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Solution

The correct option is D 225
Let work done be in 600 units.
One man do work = 100 days =6 unit/day
Now, 10 men + 15 women can do work =6 days =100 unit/day
10×6 unit/day +15n=100 unit/day
15n=40 unit/day
=600unit400unit/day=15 days
nwomen=15×15=225 days.

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