Question

10 men and 6 women are to be seated in a row so that no two women sit together. the number of ways they can be seated is

• A. 11! 10!
• B. $\frac{11!}{6!5!}$
• C. $\frac{11!9!}{5!}$
• D. $\frac{11!10!}{5!}$

Answer 1

The correct option is D

$\frac{11!10!}{5!}$

$\left(10\right)!.{11}_{p6}$
$=\frac{\left(10\right)!\left(11\right)!}{5!}$