Question

$10$ mens can do a work in $15$ days and $15$ women can do a work in $12$ day, if both $10$ men and $15$ women, so the work how many day the to complete the work.

Answer 1

Work done by $10$ men in $1$ day$=\frac{W}{15}$

Work done by $15$ women in $41$ day$=\frac{W}{10}$

If all these together do the work.

$(\frac{W}{15}+\frac{W}{12})\times d=W\frac{3}{20}\times d=1d=\frac{20}{3}=6.67\approx 7days$