Question

$10$ mili-moles of a monoacidic base is exactly neutralised by $50ml$ of an acid. The normality of the acid is:

• A. $0.5N$
• B. $0.2N$
• C. $0.6N$
• D. $0.4N$

Answer 1

Answer: (B)

$0.2N$

10 mili-moles solution of monacidic base, that means $moles=10\times {10}^{-3}moles$

Since it is monoacidic, n-factor = 1

Normality of acid = $1\times \frac{10\times {10}^{-3}}{0.05}=0.2N$

Hence, option B is correct.