Question

10 ml of 0.1 M solution sodium hydroxide is completely neutralised by 25 ml of 3 gram of dibasic acid in one solution the molecular weight of acid is:

• A. 225 g
• B. 250 g
• C. 300 g
• D. 150 g

Answer 1

The correct option is D 150 g

Given,

Concentration of $NaOH=0.1N$

Volume$=10mL$

Mass of Dibasic acid$=3g$

Volume$=25mL$

Using,

$n_1{M}_1{V}_1=n_2{M}_2{V}_2$

$n_2=2$

$\Rightarrow 1\times 0.1\times 10=2\times 25\times \frac{3}{M}$

$\Rightarrow M=\frac{2\times 25\times 3}{10\times 0.1}$

$\Rightarrow M=150g$