10 mL of 0.2 M acid is added to 250 mL of a buffer solution with pH = 6.34 and the pH of the solution becomes 6.32. The buffer capacity of the solution is:

0.1

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0.2

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0.3

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0.4

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Solution

The correct option is D 0.4
We know that,
Buffer capacity = $\frac{m o l e s o f a c i d o r b a s e a d d e d p e r l i t r e}{c h a n g e i n p H}$
Buffer capacity = $\frac{\frac{0.2 \times 10}{1000} \times \frac{1000}{250}}{6.34 - 6.32} = 0.4$
Hence, Buffer capacity =0.4.

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10 mL of 0.2 M acid is added to 250 mL of a buffer solution with pH = 6.34 and the pH of the solution becomes 6.32. The buffer capacity of the solution is:

The correct option is D 0.4We know that, Buffer capacity =moles of acid or base added per litre change in pH Buffer capacity =0.2×101000×10002506.34−6.32=0.4 Hence, Buffer capacity =0.4.

The correct option is D 0.4
We know that,
Buffer capacity = $\frac{m o l e s o f a c i d o r b a s e a d d e d p e r l i t r e}{c h a n g e i n p H}$
Buffer capacity = $\frac{\frac{0.2 \times 10}{1000} \times \frac{1000}{250}}{6.34 - 6.32} = 0.4$
Hence, Buffer capacity =0.4.