10 mL of a sample of H 2 O 2 solution liberates 112 mL of O 2 gas at STP upon decomposition- Identify the correct statements-A- Normality of the sample of H 2 O 2 is 0-5 NB- 15 mL of the same sample of H 2 O 2 solution liberates 224 mL of O 2 gas at 1-5 atm and 273- CC- Milliequivalents of hypo required for the titration of liberated I 2 when 10 mL of the same sample of H 2 O 2 solution is treated with excess of acidified solution of KI are 20D- - w - v of given same sample of H 2 O 2 solution is 3-4 -

The correct options are B 15 nbsp;mL of the same sample of nbsp;H_2O_2 solution liberates 224 nbsp;mL of O_2 gas at 1.5 atm and 273^oC C Milliequivalents ...

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Byju's Answer

Standard XII

Chemistry

Salt of Weak Acid and Strong Base

10 mL of a sa...

Question

10 $m L$ of a sample of $H_{2} O_{2}$ solution liberates 112 $m L$ of $O_{2}$ gas at STP upon decomposition. Identify the correct statement(s):

Normality of the sample of

H_{2} O_{2}

is 0.5 N

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m L

of the same sample of

H_{2} O_{2}

solution liberates 224

m L

O_{2}

gas at 1.5

a t m

and

273^{o} C

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Milliequivalents of hypo required for the titration of liberated

I_{2}

when 10

m L

of the same sample of

H_{2} O_{2}

solution is treated with excess of acidified solution of

K I

are 20

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(w / v)

of given same sample of

H_{2} O_{2}

solution is 3.4%

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Solution

The correct options are
B 15 $m L$ of the same sample of $H_{2} O_{2}$ solution liberates 224 $m L$ of $O_{2}$ gas at 1.5 $a t m$ and $273^{o} C$
C Milliequivalents of hypo required for the titration of liberated $I_{2}$ when 10 $m L$ of the same sample of $H_{2} O_{2}$ solution is treated with excess of acidified solution of $K I$ are 20
D % $(w / v)$ of given same sample of $H_{2} O_{2}$ solution is 3.4%
10 $m L$ of $H_{2} O_{2}$ solution liberates 112 $m L$ of $O_{2}$ at STP.
Therefore,
1 L of $H_{2} O_{2}$ solution liberates 11.2 L $O_{2}$ at STP
Hence,
Volume strength of $H_{2} O_{2}$ solution = 11.2
$N o r m a l i t y = \frac{11.2}{5.6} = 2$
% $(w / v) = \frac{N \times 17}{10} = 3.4$ %

15 mL of same sample of $H_{2} O_{2}$ solution liberates $\frac{15 \times 112}{10}$ $m L$ $O_{2}$ at STP

$⟹ \frac{15 \times 112}{10} \times \frac{2}{3} \times 2 = 224$ $m L$ $O_{2}$ at 1.5 $a t m$ and $273^{o} C$ .

milliequivalents sample of $H_{2} O_{2}$ reacted with $K I$
= $N \times V$
= $2 \times 10$
= 20
milliequivalents of hypo required = 20

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10 mL of a sample of H2O2 solution liberates 112 mL of O2 gas at STP upon decomposition. Identify the correct statement(s):

10 $m L$ of a sample of $H_{2} O_{2}$ solution liberates 112 $m L$ of $O_{2}$ gas at STP upon decomposition. Identify the correct statement(s):