Question

$10$ mL of a solution of $H_2{O}_2$ requires $25$ mL of $0.1$ N $KMn{O}_4$ for complete reaction. The volume strength of $H_2{O}_2$ is:

• A. $1.4$
• B. $1.2$
• C. $0.25$
• D. $2.5$

Answer 1

Answer: (A)

$1.4$

$2MnO{4}^{-}+6H^{+}+S{H}_2{O}_2\to 2M{n}^{2+}+8H_{2}O+50$

$5H_2{O}_2=2Mn{O}_4^{-}$

$\frac{5H_2{O}_2}{2Mn{O}_4^{-}}\frac{x}{y}\frac{moles}{moles}$

Molarity $=\frac{moles}{volumes}$

$0.5=\frac{molesofMn{O}_4^{-}}{Volume}$

Moles of $Mn{O}_4^{-}=0.5\times 0.025$

Moles of $H_2{O}_2=\frac{5}{2}\times 0.5\times 0.025$

Molarity $=\frac{moles}{V}$

Volume Strength $=$ Molarity $\times 112$

$=1.4$ Ans