10 mL of a solution of NaOH is found to be completely neutralised by 8mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH,
the amount HCl solution (the same solution as before) required to neutralise will be
16mL
16 mL. Since the quantity of NaOH solution is doubled, it will require the double quantity of HCl solution too.