Question

$10$ mL of a solution of $NaOH$ is found to be completely neutralized by $8$ mL of a given solution of $HCl$. If we take $20$ mL of the same solution of $NaOH$, the amount of $HCl$ solution (the same solution as before) required to neutralize it will be :

• A. $4$ mL
• B. $8$ mL
• C. $12$ mL
• D. $16$ mL

Answer 1

The correct option is D $16$ mL

Since, $10$ ml of $NaOH$ require $8$ ml $HCl$ for complete neutralisation.
$20$ ml of $NaOH$ required $HCl$ for complete neutralisation = $\frac{8\times 10}{20}$ $=16$ ml