Question

# 10 mL of a stock solution of 1 M HCl is serially diluted thrice. Each step of the serial dilution dilutes the original solution by half. What will be its final concentration?

A
0.5 M
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B
0.125 M
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C
0.025 M
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D
0.25 M
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Solution

## The correct option is C 0.125 MFor first dilution M1V1=M2V2 where M1 and V1 are the molarity and the volume of the initial solution respectively. M2 and V2 are the molarity and the volume after first dilution. M1V1V2=M2 So, M2 = 0.5 M For second dilution, M2V2=M3V3 where ,M3 and V3 are the molarity and the volume after second dilution. M2V2V3=M3 So, M3 = 0.25 M For third dilution, M3V3=MfVf where, Mf and Vf are the molarity and the volume of the final solution. M3V3Vf=Mf So, Mf = 0.125 M On each dilution, the concentration is halved, and the total volume is doubled.

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